A vessel's displacement is 300 tons has 15 tons of deck cargo. What will be the shift in the center of gravity after you move the cargo to the hold a vertical distance of 8 feet?
SOLUTION:
Shift in the center of gravity = (weight x distance) ÷ displacement
gg1 = ( 15 tons x 8 feet ) ÷ 300 tons
= 120 ÷ 300
= 0.4 feet is the answer
SOLUTION:
Shift in the center of gravity = (weight x distance) ÷ displacement
gg1 = ( 15 tons x 8 feet ) ÷ 300 tons
= 120 ÷ 300
= 0.4 feet is the answer
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| Shift In The Center Of Gravity |
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